1. Latihan Soal Fisika Kelas Xii Semester Ganjil
2. Soal Fisika Kelas X Tentang Gerak Parabola
3. Kumpulan Soal Ujian Fisika Kelas X
4. Kumpulan Soal Fisika Kelas X Kurikulum 2013

Two vectors of 6 units in magnitude and 8 units in magnitude make an angle of 90 o. The resultant force of these vectors is.. 24 units Result: F R = (F x 2 + F y 2) 1/2 = (6 2 + 8 2) 1/2 = (36 + 64) 1/2 = (100) 1/2 = 10 N 2. The magnitude of vector A is 3 units and vector B is 4 units. If the addition of vectors A and B ( A + B) is 5 units, the angle made by these two vectors is.. 90 o Result: R = (A 2 + B 2 + 2 A.B cos α) 1/2 5 = (3 2 + 4 2 + 2.3.4 cos α) 1/2 25 = (3 2 + 4 2 + 2.3.4 cos α) 25 = (9 + 16 + 24 cos α) 25 = 25 + 24 cos α 25 - 25 = 24 cos α 0 = 24 cos α cos α = 0 α = arc cos -1 0 α = 90 o 3.

One vector of 10 units in magnitude directed to the right and another of 5 units in magnitude is directed to the left act on an object. To maintain the object at rest, we need an additional vector of.. 10 units in magnitude that is directed to the right b. 15 units in magnitude that is directed to the left c.

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Latihan Soal Fisika Kelas Xii Semester Ganjil

5 units in magnitude that is directed to the right d. 5 units in magnitude that is directed to the left e. Zero length Result: ∑F = 0 F x+ + F x- + F r = 0 10 + (-5) + F r = 0 F r = 5 - 10 F r = -5 (minus sign shows that the direction is to the left). Look at the following scheme. The magnitude of the component of resultant vector to X and Y directions are.. F x = (3√3 - 2√2), F y = (3 + 2√2) b.

F x = (3√3 - 2√2), F y = (3√2 + 2√2) c. F x = (3√3 + 2√2), F y = (3 + 2√2) d. F x = (3√3 + 2√2), F y = (3√2 + 2√2) e. F x = (3√3 - 2√2), F y = (3√3 + 2√2) Result: F x = 6 units cos 30 + 4 units cos 135 F x = 6 units 0.5√3 - 4 units 0.5√2 F x = 3√3 - 2√2; F y = 6 units sin 30 + 4 units sin 135 F y = 6 units 0.5 + 4 units 0.5√2 F y = 3 + 2√2. The answer is A. Vector A of 20 units in magnitude makes an angle of 45 o. With respect to the +X direction.

Soal Fisika Kelas X Tentang Gerak Parabola

The components of this vector in the X and Y directions are.. A x = 20 units, A y = 20 units b. A x = 20√2 units, A y = 20√2 units c. A x = 10 units, A y = 10 units d. A x = 10√2 units, A y = 10√2 units e.

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A x = 10√3 units, A y = 10√2 units Result: A x = 20 units cos 45 A x = 20 units 0.5√2 A x = 10√2 A y = 20 units sin 45 A y = 20 units 0.5√2 A y = 10√2 The answer is D. Look at the following figure. The resultant force of the three vectors is.. 10√3 units Result: F x = 10units cos 60 + 5units cos 180 + 5units cos 300 F x = 10units (0.5) + 5units (-1) + 5units (0.5) F x = 5 - 5 + 2.5 F x = 2.5; F y = 10units sin 60 + 5units sin 180 + 5units sin 300 F y = 10units (0.5√3) + 5units (0) + 5units (-0.5√3) F y = 5√3 + 0 - 2.5√3 F y =2.5√3 R = √(F x 2+F y 2) = √(2.5 2+2.5√3 2) = 5 The answer is B. Two vectors, F 1 and F 2, make an angle of 105 o.

The resultant of these two vectors makes an angle of 60 o with respect to vector F 2. If the magnitude of vector F 2 is 8 units, the magnitude of vector F 1 is. 2√2 units e.√6 units Result: F 1 /sin α = F 2 /sin β F 1 / sin (60) = 8 / sin (105 - 60) F 1 / sin (60) = 8 / sin (45) F 1 = 8.

Kumpulan Soal Ujian Fisika Kelas X

Sin (60) / sin (45) F 1 = 8. 1/2√3 / 1/2√2 F 1 = 4√6 units The answer is C. Look at the following figure.

Kumpulan Soal Fisika Kelas X Kurikulum 2013

The resultant of the two vectors in the figure is.. 11 units Result: 10.

An object is placed on a smooth surface, It is pulled with a force of 20 N making an angle of 60 with respeect to the surface. If the mass of the object is negative, the norm of the vertical force needed to maintain the object at rest is.. 10√2 Result: 11. Three forces A, B, and C, act on a massless body simultaneously, as shown in the following figure. The component of resultant force in the X and Y directions is.. R x = 5√3 units, R y = 5√2 units b. R x = 0 units, R y = 5 units c.